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1 Day 1 Algorithms

[2019.02.11] Divisible Sum Pairs

by 곰돌찌 2019. 2. 11.

Problem


You are given an array of  integers, , and a positive integer, . Find and print the number of  pairs where  and  +  is divisible by .

For example,  and . Our three pairs meeting the criteria are  and .

Function Description

Complete the divisibleSumPairs function in the editor below. It should return the integer count of pairs meeting the criteria.

divisibleSumPairs has the following parameter(s):

  • n: the integer length of array 
  • ar: an array of integers
  • k: the integer to divide the pair sum by

Input Format

The first line contains  space-separated integers,  and 
The second line contains  space-separated integers describing the values of .

Constraints

Output Format

Print the number of  pairs where  and  +  is evenly divisible by .

Sample Input

6 3
1 3 2 6 1 2

Sample Output

 5

Explanation

Here are the 5 valid pairs when k = 3:

* (0, 2) → ar[0] + ar[2] = 1 + 2 = 3

* (0, 5) → ar[0] + ar[5] = 1 + 2 = 3

* (1, 3) → ar[1] + ar[3] = 3 + 6 = 9

* (2, 4) → ar[2] + ar[4] = 2 + 1 = 3

* (4, 5) → ar[4] + ar[5] = 1 + 2 = 3


How I solved the problem


# 배열이 연속하는 수가 아니기 때문에 이중 반복문이 돌아야함!

# 같은 배열이 겹치지 않도록 반복문을 짜는게 중요함.

# i가 0이라면 j는 1부터 시작하도록 해서 j가 1보다 항상 크게 시작하도록 짜는 것이 중요

# 나누어질 수 있는 배열의 합의 개수를 리턴해야하기 때문에 나머지 함수 %가 0이 되는 것을 찾기


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import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
 
public class Solution {
 
    // Complete the divisibleSumPairs function below.
    static int divisibleSumPairs(int n, int k, int[] ar) {
        int result = 0;
 
        for (int i = 0; i < n; i++) {
            for (int j = i + 1; j < n; j++) {//at least, j is bigger than i
                int sum = ar[i] + ar[j]; //sum a pair of ar
 
                if (sum % k == 0) { //test if the sum is divisible
                    result++;
                }
            }
        }
 
        return result;
    }
 
    private static final Scanner scanner = new Scanner(System.in);
 
    public static void main(String[] args) throws IOException {
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
 
        String[] nk = scanner.nextLine().split(" ");
 
        int n = Integer.parseInt(nk[0]);
 
        int k = Integer.parseInt(nk[1]);
 
        int[] ar = new int[n];
 
        String[] arItems = scanner.nextLine().split(" ");
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
 
        for (int i = 0; i < n; i++) {
            int arItem = Integer.parseInt(arItems[i]);
            ar[i] = arItem;
        }
 
        int result = divisibleSumPairs(n, k, ar);
 
        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();
 
        bufferedWriter.close();
 
        scanner.close();
    }
}
 
cs

[출처 : https://www.hackerrank.com ]


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