[2018.12.18] Arrays

Problem

Objective 
Today, we're learning about the Array data structure. Check out the Tutorial tab for learning materials and an instructional video!

Task 
Given an array, , of  integers, print 's elements in reverse order as a single line of space-separated numbers.

Input Format

The first line contains an integer,  (the size of our array). 
The second line contains  space-separated integers describing array 's elements.

Constraints

• , where  is the  integer in the array.

Output Format

Print the elements of array  in reverse order as a single line of space-separated numbers.

Sample Input

4
1 4 3 2

Sample Output

2 3 4 1

How I solved the problem

# for 문을 거꾸로 돌려야함 !

# for문 안에 초기화를 n - 1로 해주는것이 핵심. (index는 0부터 시작 ==== 최대 index는 개수보다 1이 작음)

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
 
public class Solution {
 
 
 
    private static final Scanner scanner = new Scanner(System.in);
 
    public static void main(String[] args) {
        int n = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
 
        int[] arr = new int[n];
 
        String[] arrItems = scanner.nextLine().split(" ");
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
 
        for (int i = 0; i < n; i++) {
            int arrItem = Integer.parseInt(arrItems[i]);
            arr[i] = arrItem;
        }
 
        String result = "";
 
        for (int i = n - 1; i >= 0; i--) {
            result += " " + arr[i];
        }
 
        result = result.substring(1);
 
        System.out.println(result);
        scanner.close();
    }
}
 

[출처 : https://www.hackerrank.com ]